PRP in base 11 and 13 For (B^16384+1)/2, I found hitherto: (71^16384+1)/2 ... (416213^16384+1)/2 (416771^16384+1)/2 (430463^16384+1)/2 (467307^16384+1)/2 (472489^16384+1)/2 (483641^16384+1)/2
To be completed...